Oxford Revise AQA GCSE Combined Science Foundation | Chapter P9 answers

P9: Speed

Question

Answers

Extra information

Mark

AO / Specification reference

01.1

if the distance–time graph is horizontal — the object is not moving

if the line is steep — the object is moving quickly

if the line is not very steep — the object is moving slowly

one mark for one line correct

two marks for all three lines correct

2

AO1

6.5.4.1.5

01.2

D

1

AO1

6.5.4.1.5

01.3

A

1

AO1

6.5.4.1.5

01.4

B

1

AO1

6.5.4.1.5

01.5

accelerating

1

AO1

6.5.4.1.5

02.1

car A

the gradient of the line is greatest/steepest line

1

1

AO2

6.5.4.1.4

02.2

car C

the line is horizontal

1

1

AO2

6.5.4.1.4

02.3

car C

the line is curved/not a straight line/not a constant gradient or slope

1

1

AO2

6.5.4.1.4

02.4

car A

it travelled the same distance in the shortest time

1

1

AO2

6.5.6.1.4

02.5

distance = speed × time

1

AO1

6.5.6.1.4

02.6

4 minutes = 240 seconds,

7.5 km = 7500 m

7500 = speed × 240

\(\rm{speed} = \frac{7500}{240}\)

= 31 (31.25 m/s)

accept 315 with no working for the two calculation marks

accept answer that matches car given in question 02.4

1

1

1

1

AO1 × 1

AO2 × 2

6.5.6.1.4

03.1

20m to the right

1

6.5.4.1.1

03.2

displacement, distance

magnitude, distance

magnitude

1

1

1

AO1

6.5.4.1.1

6.5.4.1.3

03.3

10 m + 20 m = 30 m

1

AO1

6.5.4.1.1

6.5.4.1.3

03.4

10 – 20 = -10 m or -10 + 20 = 10 m

10 m to the right

1

1

AO2

6.5.4.1.1

6.5.4.1.3

04.1

1.5

1

AO1

6.5.4.1.2

04.2

\(\rm{speed} = \frac{\rm{distance}}{\rm{time}}
\)

1

AO1

6.5.4.1.2

04.3

26 miles = 41 834 metres

1 hour and 14 minutes = 134 minutes = 8040 seconds

\(\frac{41\;834}{8040}\)

= 5.2 m/s

AO2

6.5.4.1.2

04.4

fitness

accept answer around running having trained

1

AO1

6.5.4.1.2

04.5

\(\frac{\rm{27\ 000}}{6}\)

= 4500 seconds

= 75 minutes

1

1

1

AO1 × 1

AO2 × 2

6.5.4.1.2

05.1

straight line of best fit

1

AO3

6.5.4.1.2

05.2

point plotted at (15, 0.08)

curved line of best fit

1

1

AO2 × 1

AO3 × 1

6.5.4.1.2

05.3

A

1

AO3

6.5.4.1.2

05.4

no/will be different

cars travelled different distance in the same time

accept calculations of both average speeds for two marks

1

1

AO2

AO3

6.5.4.1.2

06.1

1.5 m/s

1

AO1

6.5.4.1.2

06.2

distance = speed × time

1

AO1

6.5.4.1.2

06.3

3 × 20

= 30 (m)

1

1

AO2

6.5.4.1.2

06.4

average

changes

1

1

AO1

6.5.4.1.2

07.1

\(\rm{acceleration} = \frac{5-2}{6}\)

= 0.5

m/s2

1

1

1

AO1

AO2

6.5.4.1.5

07.2

decelerating

decreasing

accept accelerating (negative acceleration)

1

1

AO2

6.5.4.1.5

07.3

\(
\frac{\rm{change\ in\ y}}{\rm{change\ in\ x}}=\frac{\rm{20}}{\rm{10}}
\)

= 2 m/s2

1

1

AO2

6.5.4.1.5

08.1

the point at 4.2 cm/4.4 N

1

AO3

6.5.3

08.2

force = spring constant extension

1

AO1

6.5.3

08.3

5.6 cm = 0.056 m

4.5 = spring constant × 0.056

spring constant = \(\frac{4}{0.056}\)

= 80 N/m (or 0.8N/cm)

1

1

1

1

AO1 × 1

AO2 × 3

6.5.3

08.4

yes

this is where the line starts to curve/bend/is no longer a straight line

1

1

AO3

6.5.3

09.1

B or D

1

AO2

6.5.4.1.4

09.2

\(\rm{speed} = \frac{\rm{distance}}{\rm{time}}\)

1

AO1

6.5.4.1.2

09.3

10 minutes = 600 seconds

\(\frac{400}{600}\)

= 0.67 m/s

1

1

1

AO1

AO2

6.5.4.1.2

6.5.4.1.4

09.4

between 14 mins and 22 mins

the line is steepest

1

1

AO3

6.5.4.1.4

09.5

1000 m

1

AO3

6.5.4.1.4

10.1

distance and speed are scalars

1

AO1

6.5.1.1

6.5.6.1.1

6.5.6.1.3

10.2

20 – 10 = 10 km

south

accept ten with no working for the one calculation mark

1

1

AO2

6.5.6.1.1

10.3

displacement is the position relative to a particular point

distance is the total distance that you move, which may not be the same as displacement if you change direction

1

1

AO1

AO2

6.5.6.1.1

10.4

velocity

the cyclist is giving both a magnitude and a direction

1

1

AO1

AO2

6.5.6.1.1

Loading...